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RF平面密封法兰计算GB150和ASME
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平面密封法兰计算书
项目号
ITEM NO.
Flange calculation
文件号
DOC. NO.
遵循规范: GB/T 150-2011
法兰编号
N
1
设计条件
简
图
主体
计算压力
Pc
-0.065
Mpa
设计温度
t
670
°C
筒体
材料
S30409
设计温度许用应力
[σ]
n
t
34
Mpa
法兰
材料
S30409II
常温许用应力
[σ]
f
137
Mpa
设计温度许用应力
[σ]
f
t
34
mm
常温弹性模量
E
0
195000
Mpa
设计温度弹性模量
E
t
143000
Mpa
螺栓
材料
S30409
常温许用应力
[σ]
b
137
Mpa
设计温度许用应力
[σ]
b
t
36
Mpa
公称直径
d
B
27
mm
根径
d
根
23.751
mm
数量
n
16
个
分程隔板槽面积A
r
=
0
mm
2
垫片
垫片系数
m
3
结
构
尺
寸
(mm)
法兰假定厚度
δ
f
46.1
比压力
y
69
Mpa
D
i
194.0
δ
0
11.0
垫片宽度
N
15.10
mm
D
0
445.0
δ
1
31.5
基本密封宽度
b
0
7.55
mm
D
b
387.4
h
70.0
有效密封宽度
b
6.95
mm
D
外
317.5
Le
28.8
压紧力作用中心圆D
G
303.60
mm
D
内
287.3
L
A
65.2
b
0
≤6.4mm
b= b
0
b
0
≤6.4mm
D
G
= ( D
外
+D
内
)/2
b
0
> 6.4mm
b=2.53√b
0
b
0
> 6.4mm
D
G
= D
外
- 2b
1. 螺栓受力计算
流体压力引起的总轴向力
F=
π
D
G
2
P
c
/4
=
4.705E+03
N
操作状态下需要的最小垫片压紧力
F
p
=2P
c
(π
bD
G
m+0.5A
r
m
)
=
2.586E+03
N
操作状态下需要的最小螺栓载荷
W
p
=F+F
p
=
7.291E+03
N
预紧状态下需要的最小螺栓载荷
W
a
=
π
bD
G
y+0.5A
r
y
=
457498.5561
N
操作状态下需要的最小螺栓总截面积
A
p
=W
p
/[
σ
]
b
t
=
0.0
mm
2
预紧状态下需要的最小螺栓总截面积
A
a
=W
a
/[
σ
]
b
=
3339.4
mm
2
所需螺栓总截面积
A
m
取
A
p
和
A
a
中大者,
A
m
=
3339.4
mm
2
实际螺栓总截面积
A
b
=n
π
d
根
2
/4
=
7088.81534
mm
2
判断依据:Ab≥Am, 螺栓面积
合格
操作状态螺栓设计载荷W
1
W
1
=W
p
=
7291.3
N
预紧状态螺栓设计载荷W
2
W
2
=0.5(A
m
+A
b
)[
σ
]
b
=
714333.1
N
2. 法兰力矩计算
操作
F
D
=πD
i
2
P
c
/4=
1.921E+03
N
L
D
=L
A
+0.5δ
1
=
80.95
mm
F
G
=F
P
=
2.586E+03
N
L
G
=0.5(D
b
-D
G
)=
41.9
mm
F
T
=F-F
D
=
2.784E+03
N
L
T
=0.5(L
A
+δ
1
+L
G
)=
69.3
mm
M
D
=F
D
L
D
=
1.555E+05
Nmm
外压:M
p
=F
D
(L
D
-L
G
)+F
T
(L
T
-L
G
)
M
G
=F
G
L
G
=
1.084E+05
Nmm
外压:
=
1.513E+05
Nmm
M
T
=F
T
L
T
=
1.929E+05
Nmm
内压:M
p
=M
D
+M
G
+M
T
=
4.568E+05
Nmm
M
p
(注:按照外压的值计算)
=
1.513E+05
Nmm
预紧
M
a
=W
2
L
G
=
29931806.48
Nmm
M
a
[σ]
t
f
/[σ]
f
=
7428331.536
Nmm
计算力矩 M
o
= M
p
与M
a
[σ]
f
t
/[σ]
f
中大者,M
o
=
7.428E+06
Nmm
3. 螺栓间距校核
实际间距
L=πD
b
/n
=
76.1
mm
最小间距(查GB/T150.3表7-3)
L
min
=
62.0
mm
最大间距
L
max
=
133.0
mm
判断依据: 当L
min
<=L<=L
max
,螺栓间距合格。
合格
4. 形状常数确定
h
0
=(D
i
δ
0
)
0.5
=
46.20
h/h
0
=
=
1.52
K=D
0
/D
i
=
2.29
δ
1
/δ
0
=
=
2.86
由K查表7-9
T=
1.40
查图7-3
F
1
=
0.63
Z=
1.47
查图7-4
V
1
=
0.06
Y=
2.48
查图7-7
f
=
1.00
U=
2.73
e=F
1
/H
0
=
0.01
d
1
=Uh
0
δ
0
2
/V
I
=
2.36E+05
ψ=δ
f
e+1=
=
1.63
β=4δ
f
e/3+1=
1.83
γ=ψ/T=
=
1.16
η=δ
f
3
/d
1
=
0.41
λ=γ+η=
=
1.57
5. 法兰应力校核
当Di<20δ1,且f≤1,Dil=Di+δ1
=
225.5
mm
应力
计算值(MPa)
许用值(MPa)
结论
轴向应力
σ
H
=fM
0
/(λδ
1
2
D
il
)=
21.11
1.5[
σ
]
f
t
=
51
合格
2.5[σ]
n
t
=
85
合格
径向应力
σ
R
=βM
0
/(λδ
f
2
D
i
)=
21.02
[
σ
]
f
t
=
34
合格
切向应力
σ
T
=YM
0
/(δ
f
2
D
i
)-Zσ
R
=
13.86
[
σ
]
f
t
=
34
合格
组合应力
(σ
H
+σ
R
)
/2=
21.06
[
σ
]
f
t
=
34
合格
(σ
H
+σ
T
)
/2=
17.49
[
σ
]
f
t
=
34
合格
6. 刚度校核
刚度系数
K
1
=
0.3
Mo由预紧控制时,E用E0代替
E=E0=
195000.0
Mpa
刚度指数
J=52.14V
1
M
o
/λEδ
0
2
K
1
H
o
=
=
0.049
合格
注:
1. 所有尺寸均不含腐蚀裕量。
平面密封法兰计算书
项目号
ITEM NO.
Flange calculation
文件号
DOC. NO.
As Per ASME VIII I-2021 Mandatory Appendix 2
FLANGE NAME
N1
DESIGN DATA
FIG
MAIN
Design pressure
P
1.94
Mpa
Design Temperature
t
250
°C
SHELL
Material
SA-516 70
Allowable stress @T0
S
natm
137.9
Mpa
Allowable stress @T1
S
no
137.9
Mpa
法兰几何尺寸协调性校核
FLANGE
Material
SA-105
限制值
实际值
判断
Allowable stress @T0
S
fatm
137.9
Mpa
螺栓直径
2 1/4
Allowable stress @T1
S
fo
135.64
mm
根径
53.03
Elastictiy Modules @T0
E
atm
202713
Mpa
B应大于
120.65
153.0
合格
Elastictiy Modules @T1
E
op
188980
Mpa
Rh应大于
69.85
75
合格
BOLT
Material
SA-193 B7
E应大于
57.15
67
合格
Allowable stress @T0
S
a
172.38
Mpa
h应大于
91.95
110.0
合格
Allowable stress @T1
S
b
172.38
Mpa
h应大于1.5g0
30
110
合格
Nominal Bolt diameter
a
2 1/4
inch
Root diameter
d
r
53.03
mm
All dimensions are free of corrosion.
Number
n
40
Partition Area A
r
=
0
mm
2
GASKET
Gasket factor
m
3
DIMENSIONS
(mm)
B
1698.7
t
128
Seating load
y
68.95
Mpa
A
2084.0
g
o
20.0
seating width
N
60.00
mm
C
1950.0
g
1
50.7
Basic seating width
b
0
30.00
mm
D
out
1860.0
h
110.0
Effective seating width
b
13.86
mm
D
in
1740.0
R
75
Diameterof load reaction G
1832.29
mm
b
0
≤6.4mm
b= b
0
; b
0
> 6.4mm
b=2.53√b
0
b
0
≤6.4mm
G= ( D
out
+D
in
)/2; b
0
> 6.4mm
G= D
out
- 2b
1. The bolt area check
Total hydrostatic end force
H=πG
2
P/4
=
5.115E+06
N
Total joint‐contact surface compression load
H
p
=2P(πbGm+0.5A
r
m)
=
9.285E+05
N
Min. required Operating Bolt Load
W
m1
=H+H
p
=
6.044E+06
N
Min. required Gasket Seating Bolt Load
W
m2
=πbGy+0.5A
r
y
=
5499945.355
N
Required Bolt Area at operating condition
A
p
=W
m1
/S
b
=
35061.3
mm
2
Required Bolt Area at seating condition
A
a
=W
m2
/S
a
=
31905.9
mm
2
Required Bolt Area
A
m
=max(A
p
,A
a
)
=
35061.3
mm
2
Actual
bolt area
A
b
=nπd
r
2
/4
=
88335.3072
mm
2
Ab>=Am, the bolt area is OK!
Flange Design Bolt Load, Gasket Seating W
W=0.5(A
m
+A
b
)S
a
=
10635554.2
N
2. The bolting spacing check
Actual
bolt distance
B
s
=Gsin(π/n)
=
153.0
mm
Min. bolt spacing(According to TEMA)
B
min
=
120.7
mm
For vessels in lethal service, Max. bolt spacing
B
smax
=2a+6t/(m+0.5)
=
333.7
mm
Bolt pitch correction factor
B
sc
=max(sqrt(Bs/(2a+t)) , 1)
=
1.0
B
min
<=Bs
The space is OK!
Bs
<=
B
smax
The space is OK!
3. The flange load calculation
Operating
H
D
=πB
2
P
/4=
4.397E+06
N
h
D
=R+0.5g
1
=
100.325
mm
H
G
=H
P
=W
m1
-H=
9.285E+05
N
h
G
=0.5(C-G)=
58.9
mm
H
T
=H-H
D
=
7.187E+05
N
h
T
=0.5(R+g
1
+h
G
)=
92.3
mm
M
D
=H
D
h
D
B
SC
=
4.411E+08
Nmm
External pressure: M
op
=H
D
(h
D
-h
G
)+H
T
(h
T
-h
G
)
M
G
=H
G
h
G
B
SC
=
5.465E+07
Nmm
External pressure:
=
2.063E+08
Nmm
M
T
=H
T
h
T
B
SC
=
6.630E+07
Nmm
Internal:M
op
=M
D
+M
G
+M
T
=
5.620E+08
Nmm
M
op
(Note:According to internal pressure)
=
5.620E+08
Nmm
Total moment for gasket Seating,
M
atm
=Wh
G
B
SC
=
625980864.9
Nmm
4. Factor calculation
h
0
=(Bg
o
)
0.5
=
184.32
h/h
0
=
=
0.60
K=A/B=
1.227
g
1
/g
0
=
=
2.53
Factor from Figure 2-7.1
T=
1.828
FIG 2-7.2
F
=
0.791
Z=
4.960
FIG 2-7.3
V
=
0.159
Y=
9.614
FIG 2-7.6
f
=
1.567
U=
10.566
e=F/h
0
=
0.004
d
=Uh
0
g
0
2
/V=
4.915E+06
L=(t e+1)/T+t
3
/d=
=
1.274
5. Summary of stresses
When B≥20g1,B1=B
=
1698.7
mm
Operating
Actual (MPa)
Operating allowed stress(MPa)
Result
Longitudinal hub stress
S
H
=fM
op
/(Lg
1
2
B1)=
158.63
1.5S
fo
=
203.46
Safe
2.5S
no
=
344.75
Safe
Radial fla-
nge stress
S
R
=(1.33te+1)M
op
/(Lt
2
B)=
27.46
S
fo
=
135.64
Safe
Tangential f
lange stress
S
T
=YMop/(t
2
B)-ZS
R
=
57.97
S
fo
=
135.64
Safe
Combined stress
(S
H
+S
R
)/2=
93.04
S
fo
=
135.64
Safe
(S
H
+S
T
)/2=
108.30
S
fo
=
135.64
Safe
Seating
Actual (MPa)
Gasket seating allowed stress(MPa)
Result
Longitudinal hub stress
S
H
=fM
atm
/(Lg
1
2
B1)=
176.67
1.5S
fatm
=
206.85
Safe
2.5S
natm
=
344.75
Safe
Radial fla-
nge stress
S
R
=(1.33te+1)M
atm
/(Lt
2
B)=
30.58
S
fatm
=
137.9
Safe
Tangential f
lange stress
S
T
=YM
atm
/(t
2
B)-ZS
R
=
64.56
S
fatm
=
137.9
Safe
Combined stress
(S
H
+S
R
)/2=
103.63
S
fatm
=
137.9
Safe
(S
H
+S
T
)/2=
120.62
S
fatm
=
137.9
Safe
6. Rigidity calculation
Operating condition
Rigidity index
J=52.14VM
op
/B
sc
LE
op
g
o
2
K
1
h
o
=
=
0.872
Safe
Gasket seating condition
Rigidity index
J=52.14VM
atm
/B
sc
LE
atm
g
o
2
K
1
h
o
=
=
0.905
Safe
Note: 1. The regidity factor K1=0.3 for integral flange.
2. T0 means Atmospheric Temperature(gasket seating). T1 means Design Temperature(operating condition).
法兰计算GB150
法兰计算 ASME
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