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轴式吊耳及尾吊强度计算
Selected 尾吊, 轴式吊耳.
尾吊
轴式吊耳
尾吊
轴式吊耳
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AX型轴式吊耳的计算
项目号
ITEM NO.
Calculation of Type AX Trunnion Lug
文件号
DOC. NO.
本计算书是参照
HG/T21574-2018
编制的。
说明
:
This calculation
sheet
is
prepared referring to
HG/T 21574-20
1
8
.
1.
本计算书是参照
HG/T21574-2018
编制的,主要不同之处是增加了管轴与壳体连接焊缝的强度校核。(垫板与筒体连接焊缝应力值比管轴处低,故略去)
2.
黄色单元格内的数据是需要输入的。
3.
管轴与壳体连接焊缝根部宽度
a
的输入值应为焊缝根部的名义宽度减去负偏差,举例来说,如果图纸上标注的焊缝宽度为
10±1mm,
则
a
的输入值应为
9mm
。
4.
设计者应根据轴式吊耳作用在垫板和壳体上的力和力矩(即本计算书中的
Fv
、
Fh
、
M
和
M1
),采用
SW6
或
PV Elite
的局部应力计算程序,对垫板及壳体中的局部应力进行校核。
应注意
:
设备起吊时吊耳在垫板和壳体中引起的局部应力属于一次应力
,
因此校核时局部薄膜应力和最大表面应力均不应超过
1.5
倍的材料许用应力。
1
输入数据
Input Data
设备起吊重量
Equipment lifting weight
Q =
70000
kg
轴式吊耳的数量
Trunnion number
n =
2
管轴材料
Material of trunnion
20
管轴的许用拉伸和弯曲应力
Allowable tensile and compressive stress of trunnion material
[σ]=
150
MPa
管轴的许用剪应力
Allowable shear stress of trunnion
[τ]=
90
MPa
管轴外径
Diameter of trunnion
D
O
=
426
mm
管轴有效厚度
Effective thickness of trunnion
S =
18
mm
管轴长度
Length of trunnion
L =
248
mm
垫板厚度
Thickness of pad
S'=
16
mm
壳体材料
Shell material
Q345
管轴与壳体连接焊缝根部的宽度
Bottom width of groove
a =
18
mm
Weld attaching trunnion to shell
焊缝系数
weld coefficient
Φ=
0.7
钢丝绳与垂直面的夹角
Angle of sling
α =
15
°
动载系数
Dynamic factor
c =
1.65
A
t
5~10
5~10
5~20
10~25
DN
150
180
200
250
S =
10
12
14
14
L =
120
130
140
150
2
管轴强度校核
Checking strength of trunnion:
垂直力
Vertical force
F
v
=Q / n×9.81×c=
566527.5
N
水平力
Horizontal force
F
h
=F
v
×tanα=
151800.59
N
纵向弯矩
Longitudinal bending moment
M =F
v
×L=
1.40E+08
N·mm
管轴横截面积
Cross-sectional area of trunnnion
A =π×(D
O
-S)×S=
23071.86
mm
2
管轴内外径比值
Ratio of inside diametr to outside diameter
α=(D
O
-2S)/D
O
=
0.92
管轴的惯性矩
Moment of inertia
J =π×D
O
4
×(1-α
4
)/64=
4.81E+08
mm
4
管轴的断面模数
Section modulus
W =J / (0.5D
O
)=
2.26E+06
mm
3
2258279.8
拉伸应力 Tensile stress
σ
Lt
=F
h
/ A=
6.58
MPa
弯曲应力
Bending stress
σ
Lb
=M / W=
62.21
MPa
组合应力
Combined stress
σ
L
=
|
σ
Lt
|
+ σ
Lb
=
68.79
MPa
σL ≤ [σ] , 管轴组合应力校核合格,the combined stress in trunnion is satisfactory.
剪切应力
Shear stress
τ =F
v
/ A=
24.55
MPa
组合应力 Combined stress
σ
C
=sqrt(σ
L
2
+τ
2
)=
73.05
σC ≤ [σ] , 组合应力合格,it is satisfactory.
3
耳轴与端板连接角焊缝强度校核
Checking strength of weld of trunnion to end plate:
剪切应力
Shear stress
τ
h
=F
h
/ 1.76SD
O
=
11.25
MPa
τ
h
≤
0.7[τ]
合格,It is safe
4
轴耳与筒节连接角焊缝强度校核
Checking strength of welds of trunnion to shell
焊缝底部的外径
Outside diameter of root of weld
D
O1
=D
O
+2a=
462
mm
焊缝根部的内外径比值
Ratio of inside to outside diameter of weld root
α
1
=D
O
/D
O1
=
0.92
焊缝根部的截面积
Sectional area of weld root
A
1
=π×(D
O1
-a)×a=
25107.61
mm
2
焊缝根部的惯性矩
Moment of inertia of weld root
J
1
=π×D
O1
4
×(1-α
1
4
)/64=
6.20E+08
mm
4
焊缝根部的断面模数
Section modulus of weld root
W
1
=J
1
/(0.5D
O1
)=
2.68E+06
mm
3
弯矩
Bending moment
M
1
=F
v
×(L+S')=
1.50E+08
N.mm
焊缝的拉伸应力 Tensile stress of weld
σ
wt
=F
h
/A
1
=
6.05
Mpa
焊缝的弯曲应力
Bending stress of weld
σ
wb
=M
1
/W
1
55.75
Mpa
焊缝的组合应力
Combined stress in weld
σ
w
=σ
wt
+σ
wb
=
61.80
Mpa
σ
w
≤
[σ]
合格,It is safe
焊缝的剪切应力
Shear stress of weld
τ
w
=F
v
/A
1
=
22.56
MPa
组合应力
Combined stress
σ
wc
=sqrt(σ
w
+τ
w
)=
65.79
MPa
σ
wc
≤
[σ]
合格,It is safe
Calculation Sheet of
Doc. No._________
Tailing Lug
Page ____of____
Equipment empty weight
Q =
70000
kg
Tailing lug number
n =
1
Material of tailing lug
20
HG/T21574-92
Allowable stress
[σ] =
#REF!
MPa
Allowable shear stress
[τ] =
#REF!
MPa
TP1
TP2
TP3
TP4
TP7
TP10
Lug thickness
S =
16
mm
S
16
20
28
34
42
48
Thickness of
pad
S
'=
10
mm
Lug base width
B =
175
mm
B=2(L×tan15°+R)=
175.026
248.4619
248.4619
248.4619
256.4619
296.4619
l
ength of tailing lug
L =
140
mm
L
140
180
180
180
180
180
Length of
moment
L
'=L+S'
=
150
mm
Lift hole diameter
D =
50
mm
D
50
76
76
76
80
100
Length of R
R =
50
mm
R
50
76
76
76
80
100
Fillet weld coefficient
Φa=
0.7
Max.angle of sling
α =
30
°
Dynamic factor
c =
1.65
F1 =
Q / 2n×9.8×c
=
565950
N
F2 =
F1×tanα
=
326751.38
N
F3 =
F1 / cosα
=
653502.77
N
Stress check of lug at lug hole:
σ1=
F3/[(2R-D)×S]
tensile stress
=
816.88
MPa
#REF!
[σ]
τl =
σl
Shear strees
=
816.88
MPa
#REF!
[τ]
#REF!
Stress check of lug at fillet weld:
M =
F2×L
'
Lifting moment
=
49012707.73
N·mm
W =
SB
2
/ 6
Section modulus
=
81666.66667
mm
3
σ2=
M / W
Bending stress
=
600.16
MPa
σ3=
F1 / BS
tensile stress
=
202.13
MPa
τ2 =
F2 / BS
Shear strees
=
116.70
MPa
σ =
sqrt[(σ2+σ3)
2
+4τ2
2
]
Composite stress
=
835.54
MPa
Φa[σ]=
#REF!
MPa
#REF!
the local stress of shell and pad will be checked by SW6-1998 or PVElite
AXA Trunnion
Tailing lug
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