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轴式吊耳及尾吊强度计算

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Selected 尾吊, 轴式吊耳.
  • 尾吊
  • 轴式吊耳
  • 尾吊
  • 轴式吊耳
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AX型轴式吊耳的计算 项目号 ITEM NO.
Calculation of Type AX Trunnion Lug 文件号 DOC. NO.
本计算书是参照HG/T21574-2018编制的。                                            说明:
This calculation sheet is prepared referring to HG/T 21574-2018. 1. 本计算书是参照HG/T21574-2018编制的,主要不同之处是增加了管轴与壳体连接焊缝的强度校核。(垫板与筒体连接焊缝应力值比管轴处低,故略去)
2. 黄色单元格内的数据是需要输入的。
3. 管轴与壳体连接焊缝根部宽度a的输入值应为焊缝根部的名义宽度减去负偏差,举例来说,如果图纸上标注的焊缝宽度为10±1mm, 则a的输入值应为9mm。
4. 设计者应根据轴式吊耳作用在垫板和壳体上的力和力矩(即本计算书中的Fv、Fh、M和M1),采用SW6或PV Elite的局部应力计算程序,对垫板及壳体中的局部应力进行校核。 应注意: 设备起吊时吊耳在垫板和壳体中引起的局部应力属于一次应力, 因此校核时局部薄膜应力和最大表面应力均不应超过1.5倍的材料许用应力。
1 输入数据 Input Data
设备起吊重量 Equipment lifting weight Q = 70000 kg
轴式吊耳的数量 Trunnion number n = 2
管轴材料 Material of trunnion 20
管轴的许用拉伸和弯曲应力Allowable tensile and compressive stress of trunnion material [σ]= 150 MPa
管轴的许用剪应力 Allowable shear stress of trunnion [τ]= 90 MPa
管轴外径 Diameter of trunnion DO = 426 mm
管轴有效厚度 Effective thickness of trunnion S = 18 mm
管轴长度 Length of trunnion L = 248 mm
垫板厚度 Thickness of pad S'= 16 mm
壳体材料 Shell material Q345
管轴与壳体连接焊缝根部的宽度  Bottom width of groove                                               a = 18 mm
Weld attaching trunnion to shell 
焊缝系数 weld coefficient Φ= 0.7
钢丝绳与垂直面的夹角 Angle of sling α = 15 °
动载系数 Dynamic factor c = 1.65
1
A
t 5~10 5~10 5~20 10~25
DN 150 180 200 250
S = 10 12 14 14
L = 120 130 140 150
2 管轴强度校核 Checking strength of trunnion:
垂直力 Vertical force Fv =Q / n×9.81×c= 566527.5 N
水平力 Horizontal force Fh =Fv×tanα= 151800.59  N
纵向弯矩 Longitudinal bending moment M =Fv×L= 1.40E+08 N·mm
管轴横截面积 Cross-sectional area of trunnnion  A =π×(DO-S)×S= 23071.86  mm2
管轴内外径比值 Ratio of inside diametr to outside diameter α=(DO-2S)/DO= 0.92 
管轴的惯性矩 Moment of inertia J =π×DO4×(1-α4)/64= 4.81E+08 mm4
管轴的断面模数 Section modulus W =J / (0.5DO)= 2.26E+06 mm3 2258279.8
拉伸应力 Tensile stress σLt =Fh / A= 6.58  MPa
弯曲应力 Bending stress  σLb =M / W= 62.21  MPa
组合应力 Combined stress σL =|σLt| + σLb= 68.79  MPa
 σL ≤ [σ] , 管轴组合应力校核合格,the combined stress in trunnion is satisfactory.
剪切应力 Shear stress τ =Fv / A= 24.55  MPa
组合应力 Combined stress σC=sqrt(σL 2+τ2)= 73.05 
 σC ≤ [σ] , 组合应力合格,it is satisfactory.
3 耳轴与端板连接角焊缝强度校核 Checking strength of weld of trunnion to end plate:
剪切应力 Shear stress τh =Fh / 1.76SDO= 11.25  MPa
τh  ≤ 0.7[τ] 合格,It is safe
4 轴耳与筒节连接角焊缝强度校核 Checking strength of welds of trunnion to shell
焊缝底部的外径 Outside diameter of root of weld DO1=DO+2a= 462 mm
焊缝根部的内外径比值Ratio of inside to outside diameter of weld root  α1=DO/DO1= 0.92 
焊缝根部的截面积 Sectional area of weld root A1=π×(DO1-a)×a= 25107.61  mm2
焊缝根部的惯性矩 Moment of inertia of weld root  J1=π×DO14×(1-α14)/64= 6.20E+08 mm4
焊缝根部的断面模数 Section modulus of weld root W1=J1/(0.5DO1)= 2.68E+06 mm3
弯矩 Bending moment M1=Fv×(L+S')= 1.50E+08 N.mm
焊缝的拉伸应力 Tensile stress of weld σwt=Fh/A1= 6.05  Mpa
焊缝的弯曲应力 Bending stress of weld σwb=M1/W1 55.75  Mpa
焊缝的组合应力 Combined stress in weld σw=σwt+σwb= 61.80  Mpa
σw ≤ [σ]  合格,It is safe
焊缝的剪切应力 Shear stress of weld τw =Fv/A1= 22.56  MPa
组合应力 Combined stress σwc=sqrt(σw+τw)= 65.79  MPa
σwc ≤ [σ]  合格,It is safe

Calculation Sheet of Doc. No._________
Tailing Lug Page ____of____
Equipment empty weight Q = 70000 kg
Tailing lug number n = 1
Material of tailing lug 20 HG/T21574-92
Allowable stress [σ] = #REF! MPa
Allowable shear stress [τ] = #REF! MPa TP1 TP2 TP3 TP4 TP7 TP10
Lug thickness S = 16 mm S 16 20 28 34 42 48
Thickness of pad
S'=
10 mm
Lug base width B = 175 mm
B=2(L×tan15°+R)=
175.026 248.4619 248.4619 248.4619 256.4619 296.4619
length of tailing lug L = 140 mm L 140 180 180 180 180 180
Length of moment
L '=L+S'=
150 mm
Lift hole diameter D = 50 mm D 50 76 76 76 80 100
Length of R R = 50 mm R 50 76 76 76 80 100
Fillet weld coefficient Φa= 0.7
Max.angle of sling α = 30 °
Dynamic factor c = 1.65
1
F1 = Q / 2n×9.8×c
= 565950 N
F2 = F1×tanα
= 326751.38  N
F3 = F1 / cosα
= 653502.77  N
Stress check of lug at lug hole:
 σ1= F3/[(2R-D)×S] tensile stress
= 816.88  MPa #REF! [σ]
τl = σl Shear strees
= 816.88  MPa #REF! [τ]
#REF!
Stress check of lug at fillet weld:
M = F2×L' Lifting moment
= 49012707.73 N·mm
W = SB2 / 6 Section modulus
= 81666.66667 mm3
σ2= M / W Bending stress
= 600.16  MPa
σ3= F1 / BS tensile stress
= 202.13  MPa
τ2 = F2 / BS Shear strees
= 116.70  MPa
σ = sqrt[(σ2+σ3)2+4τ22] Composite stress
= 835.54  MPa
Φa[σ]= #REF! MPa
#REF!
the local stress of shell and pad will be checked by SW6-1998 or PVElite
AXA Trunnion
Tailing lug
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